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x^2-51x+540=1080
We move all terms to the left:
x^2-51x+540-(1080)=0
We add all the numbers together, and all the variables
x^2-51x-540=0
a = 1; b = -51; c = -540;
Δ = b2-4ac
Δ = -512-4·1·(-540)
Δ = 4761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4761}=69$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-51)-69}{2*1}=\frac{-18}{2} =-9 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-51)+69}{2*1}=\frac{120}{2} =60 $
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